%I
%S 0,1,3,4,8,5,16,16,24,15,36,38,44,37,64,62,86,59,108,102,116,97,150,
%T 130,186,125,224,178,224,177,270,230,320,219,370,280,376,281,454,348,
%U 498,327,552,394,600,413,624,488,746,475,790,556,842,585,884,636,1010
%N a(n) = (A253079(n)1)/4.
%C It almost looks like one should be able to guess a recurrence. It would be nice to know more.
%H <a href="/index/Ce#cell">Index entries for sequences related to cellular automata</a>
%Y Cf. A253079, A253080.
%K nonn
%O 0,3
%A _N. J. A. Sloane_, Feb 04 2015
